document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=353815>Question 353815</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars start from the same place and travel in opposite directions. One runs at an average rate of 24 kilometers per hour faster than the other. Find their rates if after 6 hours, they are 702 km apart. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #252917 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=252917\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let rate of one car be xkph<BR>\n" );
document.write( "other car rate will be x+24 kph<BR>\n" );
document.write( "..<BR>\n" );
document.write( "distance 702 from each other after 6 hours<BR>\n" );
document.write( "since they are going away from each other the effective rate will be x+x+24 = 2x+24 kph<BR>\n" );
document.write( "..<BR>\n" );
document.write( "distance = rate * time<BR>\n" );
document.write( " 702 = (2x+24) * 6<BR>\n" );
document.write( "702/6 = 2x+24<BR>\n" );
document.write( "117 =2x+24<BR>\n" );
document.write( "117-24 = 2x<BR>\n" );
document.write( "93=2x<BR>\n" );
document.write( "x= 46.5 kph<BR>\n" );
document.write( "other car rate = x+24 = 46.5 +24 = 70.5 kph<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );