document.write( "Question 353810: If the altitude and the base of a triangle are increased by 2 cm the area would increase by 19 cm2 . If the altitude is increased by 3 cm and the base is decreased by 4 cm the area will decrease by 5cm2 .Find the base and the altitude of the triangle. \n" ); document.write( "
Algebra.Com's Answer #252916 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
let altitude be x
\n" ); document.write( "and base be y
\n" ); document.write( "...
\n" ); document.write( "x+2
\n" ); document.write( "y+2
\n" ); document.write( "area increased by 19
\n" ); document.write( "...
\n" ); document.write( "1/2 *(x+2)(y+2)=1/2 * xy +19
\n" ); document.write( "xy+2x+2y+4 =xy+19
\n" ); document.write( "2x+2y=19-4
\n" ); document.write( "2x+2y=15.......................1
\n" ); document.write( "...
\n" ); document.write( "x+3
\n" ); document.write( "y-4
\n" ); document.write( "..
\n" ); document.write( "area decreased by 5
\n" ); document.write( "...
\n" ); document.write( "1/2*(x+3)(y-4)=1/2 * xy-5
\n" ); document.write( "xy-4x+3y-12=xy-5
\n" ); document.write( "-4x+3y=7.......................2\r
\n" ); document.write( "\n" ); document.write( "multiply equation 1 by 2
\n" ); document.write( "4x+4y=30
\n" ); document.write( "add to equation 2
\n" ); document.write( "7y=37
\n" ); document.write( "y= 5.4 cm
\n" ); document.write( "x= 2.3 cm
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );