document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=353775>Question 353775</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Noel and Joey start from two points which are 590 km apart and travel toward each other. The latter travel at 64 kilometers per hour less than two times the rate of the former. Find their rates if they meet in 5 hours. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #252914 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=252914\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let Noel's apeed be x kph<BR>\n" );
document.write( "Joey's apeed = 2x-64 kph<BR>\n" );
document.write( "...<BR>\n" );
document.write( "Since they are travelling towards each other the effective speed = x+2x-64<BR>\n" );
document.write( "= 3x-64 kph<BR>\n" );
document.write( "...<BR>\n" );
document.write( "590/3x-64 = 5<BR>\n" );
document.write( "..<BR>\n" );
document.write( "590 = 5(3x-64)<BR>\n" );
document.write( "590 = 15x-320<BR>\n" );
document.write( "15x=910<BR>\n" );
document.write( "x= 60.66 Noel's speed<BR>\n" );
document.write( "2x-64 = 2*60.66 -64 = 57.32 kph = Joey's apeed<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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