document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=353721>Question 353721</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A vessel contains 49 gallons of alcohol. A certain amount of it is drawn and the replaced by the same amount of water. Then the same amount of the mixture is drawn, after which the vessel contains only 36 gallons of pure alcohol. How many gallons was drawn each time? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #252913 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=252913\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount that was drawn each time\r<BR>\n" );
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document.write( "After this amount is drawn and replaced by water the percent of pure alcohol remaining in the mixture is (49-x)/49; after we draw x amount from the mixture again, the amount of pure alcohol is ((49-x)/49)*(49-x) and we are told that this equals 36 gal.  Soooo our equation to solve is:<BR>\n" );
document.write( "((49-x)/49)*(49-x)=36  multiply each side by 49<BR>\n" );
document.write( "(49-x)^2=1764  take the square root of both sides (we will only deal in positive #'s)<BR>\n" );
document.write( "49-x=42 or<BR>\n" );
document.write( "x=7 gal ----amount that was drawn each time<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "((49-7)/49)*(49-7)=36<BR>\n" );
document.write( "36=36\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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