document.write( "Question 353803: A man divides $10,000 among three investments at 4%, 5% and 6% per annum respectively. His total income is $515 per year. His income from the 5% and 6% investments exceeds the income at 4% by $415. Find how much is invested at each rate. \n" ); document.write( "
Algebra.Com's Answer #252912 by mananth(16946)\"\" \"About 
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A man divides $10,000 among three investments at 4%, 5% and 6% per annum respectively. His total income is $515 per year. His income from the 5% and 6% investments exceeds the income at 4% by $415. Find how much is invested at each rate.
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\n" ); document.write( "let him invest $x at 4 %
\n" ); document.write( "income from 4% = 0.04x
\n" ); document.write( "...
\n" ); document.write( "investment at5%&6% = 10,000-x
\n" ); document.write( "..
\n" ); document.write( "income from 5%&6% = 0.04x+415
\n" ); document.write( "...
\n" ); document.write( "0.04x+415 = 515
\n" ); document.write( "0.04x=100
\n" ); document.write( "x=100/0.04
\n" ); document.write( "x= 10000/4
\n" ); document.write( "x= 2500
\n" ); document.write( "Balance investment = $7500 @ 5%&6%
\n" ); document.write( "income = 415
\n" ); document.write( "5/11*415 = 188.63 interest from 5%
\n" ); document.write( "amount invested = $3772.72
\n" ); document.write( "6/11 * 415= 226.36 interest from 6%
\n" ); document.write( "Amount invested = $3772.6\r
\n" ); document.write( "\n" ); document.write( "C H E C K
\n" ); document.write( "2500*0.04 + 3772*0.05 +3772*0.06= 515
\n" ); document.write( "..
\n" ); document.write( "m.ananth@hotmail.ca\r
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