document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39845>Question 39845</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 32. Determine the coordinates for graphing the equation  3Y + 2X = 4Y – 2  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25291 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25291\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From<BR>\n" );
document.write( "3Y + 2X = 4Y – 2<BR>\n" );
document.write( "it is usually easiest to graph if we solve for y...<BR>\n" );
document.write( "3y + 2x = 4y – 2<BR>\n" );
document.write( "subtract off 3y and add 2 and get<BR>\n" );
document.write( "y = 2x + 2 <BR>\n" );
document.write( "Now there are an infinite number of coordinates that this line goes thru...<BR>\n" );
document.write( "To find a pair, merely substitute any value for x and see what value of y is generated...<BR>\n" );
document.write( "So if x = 0, y = 2 ==> the point (0, 2)<BR>\n" );
document.write( "And if x = 1, then y = 4 ==> the point (1, 4)<BR>\n" );
document.write( "and so on... </SPAN>\n" );
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