document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=353786>Question 353786</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve by completing the square\r<BR>\n" );
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document.write( "x^2-4x=10\r<BR>\n" );
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document.write( "type exact answer using radicals as needed </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #252901 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=252901\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "Step 1:  Divide by the lead coefficient.  Your lead coefficient is 1, so you don't have to do anything for step 1.\r<BR>\n" );
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document.write( "Step 2:  Put the constant term in the RHS.  Your constant term is already in the RHS, so you don't have to do anything for step 2 either.\r<BR>\n" );
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document.write( "Step 3:  Divide the first degree term coefficient by 2, square the result, and add that result to both sides of the equation. (-4 divided by 2 is -2.  -2 squared is 4)\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ 4x\ +\ 4\ =\ 10\ +\ 4\">\r<BR>\n" );
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document.write( "Step 4:  Your LHS will now be a perfect square.  Factor it.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ (x\ -\ 2)^2\ =\ 14\">\r<BR>\n" );
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document.write( "Step 5:  Take the square root of both sides remembering to consider both the positive and negative roots.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ x\ -\ 2\ =\ \pm\ \sqrt{14}\">\r<BR>\n" );
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document.write( "Step 6:  Add the opposite of the constant term in the LHS to both sides and then simplify the RHS (if possible - look for perfect square factors in the radicand).\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ 2\ \pm\ \sqrt{14}\"><BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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