document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=353767>Question 353767</A>: <I><SPAN STYLE=\"word-break: break-all;\"> TWO CARS LEAVE AN INTERSECTION AT THE SAME TIME. ONE TRAVELS NORTH AND THE OTHER HEADS SOUTH TRAVELING 10MPH FASTER. AFTER ONE HOUR, THEY ARE 50 MILES APART. WHAT WERE THEIR SPEEDS? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #252885 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=252885\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> they are traveling in opposite directions.<BR>\n" );
document.write( "let one car travel at xmph<BR>\n" );
document.write( "the other travels at x+10 mph<BR>\n" );
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document.write( "Since they are traveling in opposite direction ,colinesr add up the speeds.<BR>\n" );
document.write( "Their effective speed = x+1+10 mph= 2x+10 mph.<BR>\n" );
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document.write( "time = distance /speed<BR>\n" );
document.write( "time = 1 hour<BR>\n" );
document.write( "speed = 2x+10 mph<BR>\n" );
document.write( "distance = 50 miles<BR>\n" );
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document.write( "1 = 50/(2x+10)<BR>\n" );
document.write( "2x+10 = 50<BR>\n" );
document.write( "2x=50-10<BR>\n" );
document.write( "2x=40<BR>\n" );
document.write( "x= 20 mph<BR>\n" );
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document.write( "x+10 = 30 mph.<BR>\n" );
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document.write( "C H E C K<BR>\n" );
document.write( "After 1 hour they will be 20+30 miles apart. = 50 miles.<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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