document.write( "Question 353719: After walking a distance of 6 miles at a certain rate, a man decided to increase his rate per hour by 1 mile and walked 5 miles farther. Had he walked the entire distance of 11 miles at his former rate, his time would have been 15 minutes longer. Find his former rate. \n" ); document.write( "
Algebra.Com's Answer #252871 by stanbon(75887)\"\" \"About 
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After walking a distance of 6 miles at a certain rate, a man decided to increase his rate per hour by 1 mile and walked 5 miles farther.
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\n" ); document.write( "Had he walked the entire distance of 11 miles at his former rate, his time would have been 15 minutes longer. Find his former rate.
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\n" ); document.write( "1st segment DATA:
\n" ); document.write( "distance = 6 miles ; rate = x mph ; time = 6/x hrs.
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\n" ); document.write( "2nd segment DATA:
\n" ); document.write( "distance = 5 miles ; rate = x+1 mph ; time = 5/(x+1) hrs.
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\n" ); document.write( "Total distance DATA:
\n" ); document.write( "distance = 11 miles ; rate = x ; time = d/r = 11/x hrs
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\n" ); document.write( "Equation:
\n" ); document.write( "(time + time) - time = (1/4)hrs
\n" ); document.write( "[11/x] -[6/x + 5/(x+1)] = 1/4
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\n" ); document.write( "Multiply thru by 4x(x+1) to get:
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\n" ); document.write( "11*4(x+1) - [6*4*(x+1) + 5*4x] = x(x+1)
\n" ); document.write( "44x+44 - 24x-24 - 20x = x^2+x
\n" ); document.write( "20 = x^2+x
\n" ); document.write( "x^2+x-20 = 0
\n" ); document.write( "(x+5)(x-4) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 4 mph
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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