document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=353720>Question 353720</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has one solution that is 80% acid and another that is 30% acid.  He needs 200 liters of a solution that is 62% acid.  How much of each should be used?\r<BR>\n" );
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document.write( "Let    x=number of liters of 80% solution<BR>\n" );
document.write( "       Y= number of liters of 30% solution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #252845 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=252845\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist has one solution that is 80% acid and another that is 30% acid. He needs 200 liters of a solution that is 62% acid. How much of each should be used? <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.80x + 0.30(200-x) = 0.62*200<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "80x + 30*200 - 30x = 62*200<BR>\n" );
document.write( "50x = 32*200<BR>\n" );
document.write( "x = 4*32 = 128 liters (amt. of 80% solution needed in the mixture)<BR>\n" );
document.write( "200-x = 72 liters (amt. of 30% solution needed in the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
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