document.write( "Question 39848: Solve the equation and check for extraneous solutions.
\n" ); document.write( "1.5sqrt(3x-2)-3=7\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #25284 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1.5sqrt(3x-2)-3=7
\n" ); document.write( "Add 3 to both sides to get:
\n" ); document.write( "1.5sqrt(3x-1)=10
\n" ); document.write( "Multiply both sides by 2/3 to get:
\n" ); document.write( "sqrt(3x-1)=20/3
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "3x-1=400/9
\n" ); document.write( "Add 9/9 to both sides to get:
\n" ); document.write( "3x=409/9
\n" ); document.write( "Divide by 3 to get:
\n" ); document.write( "x=15.148148148...
\n" ); document.write( "Check in the original equation.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" ); document.write( "
\n" );