document.write( "Question 353686: the perimeter of a rectangle is 160 m. the length is 8m more than twice the width. find the dimensions \n" ); document.write( "
Algebra.Com's Answer #252839 by jsmallt9(3758)\"\" \"About 
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Let L = length and W = width.
\n" ); document.write( "\"The length is 8m more than twice the width\" translates into:
\n" ); document.write( "L = 8 + 2W
\n" ); document.write( "From the information on the perimeter we also know that
\n" ); document.write( "160 = 2L + 2W

\n" ); document.write( "We can solve this system in several ways. Since the first equation is already soved for L, I will use the Substitution Method and substitute for L in the second equation:
\n" ); document.write( "160 = 2(8 + 2W) + 2W
\n" ); document.write( "Simplify:
\n" ); document.write( "160 = 16 + 4W + 2W
\n" ); document.write( "160 = 16 + 6W
\n" ); document.write( "Subtract 16 from each side:
\n" ); document.write( "144 = 6W
\n" ); document.write( "Divide both sides by 6:
\n" ); document.write( "24 = W
\n" ); document.write( "With L = 8 + 2W we can find L:
\n" ); document.write( "L = 8 + 2(24)
\n" ); document.write( "L = 8 + 48
\n" ); document.write( "L = 56

\n" ); document.write( "To check you can make sure that with a length of 56 and a width of 24 the...
\n" ); document.write( "- the perimeter is 160, and
\n" ); document.write( "- the length is 8 more that twice the width.
\n" ); document.write( "This answer checks. \n" ); document.write( "
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