document.write( "Question 353690: The larger of two consecutive integers is 11 more than one half the smaller \n" ); document.write( "

Algebra.Com's Answer #252838 by jsmallt9(3758) $\"\"$ $\"About$

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Let x = the larger integer.
\n" ); document.write( "Then x-1 would be the next smaller integer.
\n" ); document.write( "Now \"The larger of two consecutive integers is 11 more than one half the smaller.\" translates into:
\n" ); document.write( " $\"x+=+11+%2B+%281%2F2%29%28x-1%29\"$
\n" ); document.write( "Simplifying we get:
\n" ); document.write( " $\"x+=+11+%2B+%281%2F2%29x-1%2F2%29\"$
\n" ); document.write( "Get rid of the fractions by multiplying both sides by 2:
\n" ); document.write( " $\"2x+=+22+%2B+x+-+1\"$
\n" ); document.write( " $\"2x+=+21+%2B+x\"$
\n" ); document.write( "Subtracting x from each side we get:
\n" ); document.write( " $\"x+=+21\"$
\n" ); document.write( "\"x\", as we said earlier, is the larger integer and \"x-1\" or 20 is the smaller integer. To check you can easily determine that the larger number, 21, is actually 11 more than half of the smaller, 20. \n" ); document.write( "

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