document.write( "Question 353686: the perimeter of a rectangle is 160 m. the length is 8m more than twice the width. find the dimensions \n" ); document.write( "
Algebra.Com's Answer #252836 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=W+8 \n" ); document.write( "2L+2W=160 \n" ); document.write( "2(W+8)+2W=160 \n" ); document.write( "2W+16+2W=160 \n" ); document.write( "4W=160-16 \n" ); document.write( "4W=144 \n" ); document.write( "W=144/4 \n" ); document.write( "W=36 ANS. FOR THE WIDTH. \n" ); document.write( "L=36+8=44 ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "2*44+2*36=160 \n" ); document.write( "88+72=160 \n" ); document.write( "160=160 \n" ); document.write( " |