document.write( "Question 353686: the perimeter of a rectangle is 160 m. the length is 8m more than twice the width. find the dimensions \n" ); document.write( "
Algebra.Com's Answer #252836 by checkley77(12844)\"\" \"About 
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L=W+8
\n" ); document.write( "2L+2W=160
\n" ); document.write( "2(W+8)+2W=160
\n" ); document.write( "2W+16+2W=160
\n" ); document.write( "4W=160-16
\n" ); document.write( "4W=144
\n" ); document.write( "W=144/4
\n" ); document.write( "W=36 ANS. FOR THE WIDTH.
\n" ); document.write( "L=36+8=44 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*44+2*36=160
\n" ); document.write( "88+72=160
\n" ); document.write( "160=160
\n" ); document.write( "
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