document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=353700>Question 353700</A>: <I><SPAN STYLE=\"word-break: break-all;\"> you invest $20,000 in two accounts paying 7% and 8% annual interest. how much should be invested at each rate if the total interest earned for the year is to be $1520? Begin by filling in the missing entry in the following table.\r<BR>\n" );
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document.write( "              principal  x  rate = interest<BR>\n" );
document.write( "7% interest       x          0.07    0.07x<BR>\n" );
document.write( "8% interest   20,000-x       0.09        </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #252830 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=252830\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .08x+.07(20,000-x)=1,520<BR>\n" );
document.write( ".08x+1,400-.07x=1,520<BR>\n" );
document.write( ".-1x=1,520-1,400<BR>\n" );
document.write( ".01x=120<BR>\n" );
document.write( "x=120/.01<BR>\n" );
document.write( "x=12,000 amount invested @ 9%<BR>\n" );
document.write( "20,000-12,000=8,000 invested @ 8%.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".08*12,000+.07*8,000=1,520<BR>\n" );
document.write( "960+560=1,520<BR>\n" );
document.write( "1,520=1,520<BR>\n" );
document.write( "  </SPAN>\n" );
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