document.write( "Question 353479: Mason & Joe walked to a dock at 3 miles per hour, got on a boat, and traveled, to dillion at 8 miles per hour. if the total distance was 19 miles and the trip took 4.25 miles in all, how far did they go? \n" ); document.write( "
Algebra.Com's Answer #252826 by checkley77(12844)\"\" \"About 
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As you stated they went 19 miles.
\n" ); document.write( "If you looking for the average speed then:
\n" ); document.write( "D=RT
\n" ); document.write( "19=(3/X+8/(19-X))4.25
\n" ); document.write( "19=(3[19-X]+8X)/X(19-X)4.25
\n" ); document.write( "19=(57-3X+8X)/(19X-X^2)4.25
\n" ); document.write( "19=(57+5X)/(19X-X^2)4.25
\n" ); document.write( "19=4.25(57+5X)/(19X-X^2)
\n" ); document.write( "19*(19X-X^2)=242.25+21.25X
\n" ); document.write( "361X-19X^2-242.25-21.25X=0
\n" ); document.write( "-19X^2+339.75X-242.25=0
\n" ); document.write( "19X^2-339.75X+242.25=0
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "X=(339.75+-SQRT[339.75^2-4*19*242,25])/2*19
\n" ); document.write( "X=(339.75+-SQRT[115,430.0625-18,411])/38
\n" ); document.write( "X=(339.75+-SQRT97,019.0625)/38
\n" ); document.write( "X=(339.75+-311.4788)/38
\n" ); document.write( "X=(339.75-311.4788)/38
\n" ); document.write( "X=28.2712/38
\n" ); document.write( "X=.744 MILES FOR THE 3 MPH TRIP.
\n" ); document.write( "19-.744=18.256 MILES FOR THE 6 MPH BOAT TRIP.
\n" ); document.write( "PROOF:
\n" ); document.write( "19=((3/.744)+8/(18.256))4,25
\n" ); document.write( "19=(4.032+.4382)4.25
\n" ); document.write( "19=4.47*4.25
\n" ); document.write( "19~19 \n" ); document.write( "
\n" );