document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=353647>Question 353647</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three consecutive odd integers are such that the square of the third integer is 105 less than the sum of the squares of the first two.  One solution is -9, -7, and -5.  Find three other consecutive odd integers that only satisfy the given conditions. </SPAN>\n" );
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document.write( "Let integers are x, x+2, x+4 \r<BR>\n" );
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document.write( "(x+4)^2 = x^2 + (x+2)^2 - 105 \r<BR>\n" );
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document.write( "=> x^2 + 8x + 16 = x^2 + x^2 + 4x + 4 - 105\r<BR>\n" );
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document.write( "=> x^2 - 4x - 117 = 0\r<BR>\n" );
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document.write( "=> x^2 -13x + 9x -117 = 0\r<BR>\n" );
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document.write( "=> x(x-13) + 9( x-13) = 0\r<BR>\n" );
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document.write( "=> ( x+9) (x-13) = 0\r<BR>\n" );
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document.write( "x = -9  or  x = 13\r<BR>\n" );
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document.write( "other consecutive integers are  13, 15, 17.\r<BR>\n" );
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document.write( "  </SPAN>\n" );
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