document.write( "Question 352806: A rectangle has a perimeter of 42 feet. The length is 3 feet longer than the width . What is the lenght and width of the deck \n" ); document.write( "
Algebra.Com's Answer #252699 by sofiyac(983)![]() ![]() You can put this solution on YOUR website! P=2(l+w) \n" ); document.write( "if width is x then length is x+3 \n" ); document.write( "42=2(x+x+3) \n" ); document.write( "42=2(2x+3) \n" ); document.write( "21=2x+3 \n" ); document.write( "18=2x \n" ); document.write( "9=x \n" ); document.write( "so the width is 9 then the length is 9+3=12 \n" ); document.write( " |