document.write( "Question 353617: Betty invests $12,000 in two plans. One pays 6% interest and the other pays 9% interest. If the total interest is $828, how much was invested in each plan? \n" ); document.write( "
Algebra.Com's Answer #252680 by ewatrrr(24785)\"\" \"About 
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Hi,
\n" ); document.write( "Let x represent the amount invested at 6%. then (12,000-x) would be the amount remaining to be invested at 9%
\n" ); document.write( ".
\n" ); document.write( "question states;
\n" ); document.write( ".06x + .09(12,000-x) = $828
\n" ); document.write( ".
\n" ); document.write( "simplify
\n" ); document.write( ".06s + 1080 - .09x = $828
\n" ); document.write( "1080-828 = .03x
\n" ); document.write( "252 = .03x
\n" ); document.write( "$8400 = x
\n" ); document.write( ".
\n" ); document.write( "$8400 at 6% and $3600 at 9%
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