document.write( "Question 353617: Betty invests $12,000 in two plans. One pays 6% interest and the other pays 9% interest. If the total interest is $828, how much was invested in each plan? \n" ); document.write( "
Algebra.Com's Answer #252680 by ewatrrr(24785) You can put this solution on YOUR website! Hi, \n" ); document.write( "Let x represent the amount invested at 6%. then (12,000-x) would be the amount remaining to be invested at 9% \n" ); document.write( ". \n" ); document.write( "question states; \n" ); document.write( ".06x + .09(12,000-x) = $828 \n" ); document.write( ". \n" ); document.write( "simplify \n" ); document.write( ".06s + 1080 - .09x = $828 \n" ); document.write( "1080-828 = .03x \n" ); document.write( "252 = .03x \n" ); document.write( "$8400 = x \n" ); document.write( ". \n" ); document.write( "$8400 at 6% and $3600 at 9% \n" ); document.write( " |