document.write( "Question 353526: graph each relation:
\n" ); document.write( "|x|+|y|=2
\n" ); document.write( "|xy|=6
\n" ); document.write( "x|y|=4
\n" ); document.write( "|x|y=10
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Algebra.Com's Answer #252652 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
1. Solve the equation in each quadrant.
\n" ); document.write( "QI: \"x%3E0\" \"abs%28x%29=x\"
\n" ); document.write( "\"y%3E0\" \"abs%28y%29=y\"
\n" ); document.write( "\"x%2By=2\"
\n" ); document.write( "\"y=-x%2B2\"
\n" ); document.write( "QII: \"x%3C0\" \"abs%28x%29=-x\"
\n" ); document.write( "\"y%3E0\" \"abs%28y%29=y\"
\n" ); document.write( "\"-x%2By=2\"
\n" ); document.write( "\"y=x%2B2\"
\n" ); document.write( "QIII: \"x%3C0\" \"abs%28x%29=-x\"
\n" ); document.write( "\"y%3C0\" \"abs%28y%29=-y\"
\n" ); document.write( "\"-x-y=2\"
\n" ); document.write( "\"y=-x-2\"
\n" ); document.write( "QIII: \"x%3E0\" \"abs%28x%29=x\"
\n" ); document.write( "\"y%3C0\" \"abs%28y%29=-y\"
\n" ); document.write( "\"x-y=2\"
\n" ); document.write( "\"y=x-2\"
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\n" ); document.write( "Graph it but remember you can only graph quadrant by quadrant.
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\n" ); document.write( "2. \"xy=6\" and \"-xy=6\"
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\n" ); document.write( "3. \"x%2Aabs%28y%29=4\"
\n" ); document.write( "Since \"abs%28y%29\" is always positive, the function will only exist for \"x%3E0\" since \"x%3C0\" would give a negative value.
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\n" ); document.write( "4. In this case, the function only provides positive \"y\" values.
\n" ); document.write( "\"abs%28x%29%2Ay=10\"
\n" ); document.write( "\"y=10%2Fabs%28x%29\"
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