document.write( "Question 353480: a sprinkler is set in a corner of a rectangular lawn 10 ft by 25 ft. If the maximum distance the sprinkler can reacch is 10 ft --- what percent of the lawn will be watered from this position?\r
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document.write( "i have A= 10 x 25 =250 A of circle 3.14 x 5^2 = 78.54
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document.write( "solution 79/250 = .316 which is 32%. I my answer correct \n" );
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Algebra.Com's Answer #252640 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! This is all good: \n" ); document.write( "A= 10 x 25 =250 A of circle 3.14 x 5^2 = 78.54 \n" ); document.write( ". \n" ); document.write( "However, since the sprinkler is placed on a corner, only 1/4 of the water will hit the lawn -- therefore: \n" ); document.write( "area covered by sprinkler is 78.54(.25) = 19.63 \n" ); document.write( ". \n" ); document.write( "Percent coverage: \n" ); document.write( "19.63/250 = .079 or 7.9% \n" ); document.write( " |