document.write( "Question 353480: a sprinkler is set in a corner of a rectangular lawn 10 ft by 25 ft. If the maximum distance the sprinkler can reacch is 10 ft --- what percent of the lawn will be watered from this position?\r
\n" ); document.write( "\n" ); document.write( "i have A= 10 x 25 =250 A of circle 3.14 x 5^2 = 78.54
\n" ); document.write( "solution 79/250 = .316 which is 32%. I my answer correct
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Algebra.Com's Answer #252640 by nerdybill(7384)\"\" \"About 
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This is all good:
\n" ); document.write( "A= 10 x 25 =250 A of circle 3.14 x 5^2 = 78.54
\n" ); document.write( ".
\n" ); document.write( "However, since the sprinkler is placed on a corner, only 1/4 of the water will hit the lawn -- therefore:
\n" ); document.write( "area covered by sprinkler is 78.54(.25) = 19.63
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\n" ); document.write( "Percent coverage:
\n" ); document.write( "19.63/250 = .079 or 7.9%
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