document.write( "Question 353546: PLEASE HELP ME TO SOLVE THESE QUESTIONS.............\r
\n" ); document.write( "\n" ); document.write( "Q1.IF \"x%5E3%2B1%2Fx%5E3=2\" then find the value of x+1/x\r
\n" ); document.write( "\n" ); document.write( "Q2.FIND THE VALUE OF \"%28x%2By%29%5E3%2B%28x-2y%2B2%29\"\r
\n" ); document.write( "\n" ); document.write( "Q3.IF .then find the value of \"x%5E16\"\r
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Algebra.Com's Answer #252638 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
Q1.IF \"x%5E3%2B1%2Fx%5E3=2\" then find the value of x+1/x
\n" ); document.write( "Let's start by eliminating the fraction. Multiply both sides by \"x%5E3\":
\n" ); document.write( "\"x%5E6+%2B+1+=+2x%5E3\"
\n" ); document.write( "To solve a non-linear equation, we often get one side equal to zero and factor:
\n" ); document.write( "\"x%5E6+-+2x%5E3+%2B+1+=+0\"
\n" ); document.write( "Solving this equation is much easier if we notice that the exponent of 6 is twice the exponent of 3. That makes this equation in quadratic form for \"x%5E3\". Looking at the expression this way we can, perhaps, see that the expression fits the pattern: \"a%5E2+%2B+2ab+%2B+b%5E2\" which we know is, in factored form: \"%28a%2Bb%29%5E2\". So you equation factors into:
\n" ); document.write( "\"x%5E3+-+1%29%5E2+=+0\"
\n" ); document.write( "By the Zero Product Property we know that this (or any) product is zero only if one of the factors is zero. So:
\n" ); document.write( "\"x%5E3+-+1+=+0\"
\n" ); document.write( "Solving this we get x = 1.
\n" ); document.write( "This makes x + 1/x = 1 + 1/1 = 1 + 1 = 2.

\n" ); document.write( "Q2.FIND THE VALUE OF \"%28x%2By%29%5E3%2B%28x-2y%2B2%29\"
\n" ); document.write( "This problem does not make sense. You can't find a value unless you have an equation and this has no equals sign. The only thing you can do with this expression is simplify it. That means cubing (x+y) correctly (Hint: It is not \"x%5E3+%2B+y%5E3\"!) and then combining like terms, if any.

\n" ); document.write( "Q3.IF .then find the value of \"x%5E16\"
\n" ); document.write( "The first two factors\"%28x%2B1%2Fx%29%2A%28x-1%2Fx%29\" fit the pattern of (a+b)(a-b) which we know from the pattern to be equal to \"a%5E2+-+b%5E2\". So your first two factors are equal to \"x%5E2+-+1%2Fx%5E2\". But this and the third factor fit the same pattern again. So the first three factors are equal to \"x%5E4+-+1%2Fx%5E4\". But this, combined with the next factor fit the pattern again. And this repeats once more time making the entire left side of the equation equal to:
\n" ); document.write( "\"x%5E16+-+1%2Fx%5E16\". So now our equation looks like:
\n" ); document.write( "\"x%5E16+-+1%2Fx%5E16+=+3%2F2\"
\n" ); document.write( "We can solve this just like we did problem 1. Get rid of the fraction:
\n" ); document.write( "\"x%5E32+-+1+=+%283%2F2%29x%5E16\"
\n" ); document.write( "Get one side equal to zero:
\n" ); document.write( "\"x%5E32+-+%283%2F2%29x%5E16+-+1+=+0\"
\n" ); document.write( "This, like problem 1, is an equation in \"quadratic form\". This time it is in quadratic form for \"x%5E16\". This equation, unlike problem 1, does not factor easily. When we can't factor, we resort to the Quadratic Formula. This gives us:
\n" ); document.write( "\"x%5E16+=+%28-%28-3%2F2%29+%2B-+sqrt%28%28-3%2F2%29%5E2+-+4%281%29%28-1%29%29%29%2F2%281%29\"
\n" ); document.write( "Simplifying.
\n" ); document.write( "\"x%5E16+=+%28-%28-3%2F2%29+%2B-+sqrt%289%2F4+-+4%281%29%28-1%29%29%29%2F2%281%29\"
\n" ); document.write( "\"x%5E16+=+%283%2F2+%2B-+sqrt%289%2F4+%2B+4%29%29%2F2\"
\n" ); document.write( "\"x%5E16+=+%283%2F2+%2B-+sqrt%289%2F4+%2B+16%2F4%29%29%2F2\"
\n" ); document.write( "\"x%5E16+=+%283%2F2+%2B-+sqrt%2825%2F4%29%29%2F2\"
\n" ); document.write( "\"x%5E16+=+%283%2F2+%2B-+5%2F2%29%2F2\"
\n" ); document.write( "In long form this is:
\n" ); document.write( "\"x%5E16+=+%283%2F2+%2B+5%2F2%29%2F2\" or \"x%5E16+=+%283%2F2+-+5%2F2%29%2F2\"
\n" ); document.write( "Looking at the second equation, we see that the fraction will be negative. And since \"x%5E16\" cannot be equal to a negative number, there will be no solutions to the second equation. So we only have to solve the first equation. we continue by simplifying:
\n" ); document.write( "\"x%5E16+=+%288%2F2%29%2F2\"
\n" ); document.write( "\"x%5E16+=+4%2F2\"
\n" ); document.write( "\"x%5E16+=+2\"
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