document.write( "Question 353542: X + Y = 10 , 3X + Y = 12\r
\n" ); document.write( "\n" ); document.write( "I need some help trying to figure these problems out can some one please help me
\n" ); document.write( "

Algebra.Com's Answer #252599 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
X + Y = 10 , 3X + Y = 12
\n" ); document.write( "...
\n" ); document.write( "you have to eliminate either x or y . to elimiinate y we multiply equation 1 by -1
\n" ); document.write( "we get -x-y=-10.
\n" ); document.write( "add it to equation 2
\n" ); document.write( "3x+y=12
\n" ); document.write( "-x+3x-y+y=-10+12
\n" ); document.write( "2x=2
\n" ); document.write( "x=1
\n" ); document.write( "...
\n" ); document.write( "x+y =10
\n" ); document.write( "plug value of x
\n" ); document.write( "1+y =10
\n" ); document.write( "y=9
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
\n" );