document.write( "Question 353510: Phyllis invested 33000 dollars, a portion earning a simple interest rate of 5 percent per year and the rest earning a rate of 7 percent per year. After one year the total interest earned on these investments was 2090 dollars. How much money did she invest at each rate?
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Algebra.Com's Answer #252580 by robertb(5830)\"\" \"About 
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Let x = portion earning at 5% per year.
\n" ); document.write( "Then 33000 - x = portion earning at 7%.
\n" ); document.write( "Then \"0.05%2Ax%2B0.07%2A%2833000+-+x%29=2090\", the total interest after 1 year.
\n" ); document.write( "\"0.05x%2B2310-0.07x+=+2090\",
\n" ); document.write( "\"-0.02x+=+-220\",
\n" ); document.write( "\"x+=+%28-220%29%2F%28-0.02%29\"
\n" ); document.write( "\"x+=+11000\" is the investment at 5%, and
\n" ); document.write( "\"33000+-+11000+=+22000\" is the investment at 7%.
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