document.write( "Question 353506: Hello. I am a college student dealing with linear equations. I have finsihed the rest of my assignment, but I am stuck on this one problem. \r
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document.write( " x-y = 3
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document.write( "-6x+6y=17\r
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document.write( "The instructions to this problem say to Solve each system by the addition method. Determine whether the equations are independent, dependent, or inconsistent. \r
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document.write( "The example says to multiply each side by the x value. \r
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document.write( "This is what I have come up with:\r
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document.write( "x-y = 3 (1)
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document.write( "-6x + 6y = 17 (2)\r
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document.write( "I multiplied (1) by 6 and (2) by 1\r
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document.write( "I came up with \r
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document.write( " 6x-6y= 18
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document.write( "-6x+6y = 17\r
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document.write( "then I end up with both 0 x and 0 y\r
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document.write( "ox + 0y = 35\r
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document.write( "That did not give me a workable answer. \r
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document.write( "Then I tried multiplying (1) by -6 and (2) by 1 \r
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document.write( "-6x+6y = -18\r
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document.write( "-6x+6y = 17\r
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document.write( "-12x + 12y = -1\r
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document.write( "or \r
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document.write( "-6x-6y = -18
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document.write( "-6x+6y = 17\r
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document.write( "-12x+oy = -1
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document.write( "-12x = -1
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document.write( "x = -1/-12
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document.write( "x = 1/12 or .083...\r
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document.write( "That just does not seem right to me. Can you please help me figure out what I am doing wrong! \n" );
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Algebra.Com's Answer #252570 by edjones(8007)![]() ![]() You can put this solution on YOUR website! x-y = 3 \n" ); document.write( "-6x+6y=17 \n" ); document.write( ". \n" ); document.write( "6x-6y=18 \n" ); document.write( "-6x+6y=17 \n" ); document.write( "----------add \n" ); document.write( "0=35 \n" ); document.write( ". \n" ); document.write( "There is no answer. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |