document.write( "Question 346338: solve using cramers rule \r
\n" ); document.write( "\n" ); document.write( "2x+3y=4
\n" ); document.write( "4x+y=-2 \n" ); document.write( "
Algebra.Com's Answer #252548 by BlackMamba2994(1)\"\" \"About 
You can put this solution on YOUR website!
first you do the X set-up. Then the Y set-up
\n" ); document.write( "2x=A, 3y=B, 4=C, 4=D, Y(which is 1)=E and -2=F.c
\n" ); document.write( " The X set-up Looks like this:
\n" ); document.write( " (4)C (3)B 2(A) 4(C)
\n" ); document.write( " (-2)F (1)E 4(D) -2(F)
\n" ); document.write( "X=---------- Y=----------
\n" ); document.write( " (2)A (3)B 2(A) 3(B)
\n" ); document.write( " (4)D (1)E 4(D) 1(E)
\n" ); document.write( "Again cross multiply the top. And the Bottom. And It Should Be 4-6=-2 1
\n" ); document.write( "4*1 and -2*3 2*1 and 4*3 --- = X=---
\n" ); document.write( " 2+12= 14 7
\n" ); document.write( "Again cross multiply the top. And the Bottom. And It Should Be
\n" ); document.write( "2*-2 and 4*3 2*1 and 4*3
\n" ); document.write( " -4+12=8 4
\n" ); document.write( " --- = Y=---
\n" ); document.write( " 2+12=14 7 \n" ); document.write( "
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