document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=353419>Question 353419</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three times a first number and twice a second number is 8. If the second number is subtracted from twice the first number, the result if 3. Find the numbers.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #252536 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=252536\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first number = x<BR>\n" );
document.write( "second number = y<BR>\n" );
document.write( "...<BR>\n" );
document.write( "3x+2y=8.......................1\r<BR>\n" );
document.write( "\n" );
document.write( "2x-y=3........................2<BR>\n" );
document.write( "multiply equation2 by 2 and add it to equation 1<BR>\n" );
document.write( "4x-2y=6<BR>\n" );
document.write( "add to 1<BR>\n" );
document.write( "7x=14<BR>\n" );
document.write( "/7<BR>\n" );
document.write( "x= 2<BR>\n" );
document.write( "...<BR>\n" );
document.write( "plug the value of x in equation 2<BR>\n" );
document.write( "2*2-y=3<BR>\n" );
document.write( "4-y=3<BR>\n" );
document.write( "y=1<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );