document.write( "Question 353420: I don't even know where to begin on this problem. This is a question from my college Algebra 2 course.\r
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document.write( "A precious metals company receives an order for a block of 160 lbs. of alloy which is 35% silver. The block is made from two individual blocks. The first individual block was 50% silver. The second individual block was 25% silver. What were the weights of the two original blocks? \n" );
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Algebra.Com's Answer #252530 by Earlsdon(6294) ![]() You can put this solution on YOUR website! Think about the amount of silver in each of the blocks of alloy. \n" ); document.write( "The 160-lb block has 35% of 160 lbs of silver, or (0.35)(160) lbs of silver. \n" ); document.write( "The two blocks from which this is made have x(0.5) lbs of silver and (160-x)(0.25) lbs of silver. x is the weight of the block with 50% silver. \n" ); document.write( "So we set these quantities equal. \n" ); document.write( "(0.35)(160) = x(0.50)+(160-x)(0.25) Simplify and solve for x. \n" ); document.write( "56 = 0.5x+40-0.25x Subtract 40 from both sides. \n" ); document.write( "16 = 0.5x-0.25x Simplify. \n" ); document.write( "16 = 0.25x Divide both sides by 0.25 \n" ); document.write( "64 = x and... \n" ); document.write( "160-x = 96 \n" ); document.write( "The weights of the original blocks were: \n" ); document.write( "64 lbs of the 50% silver alloy and 96 lbs of the 25% silver alloy. \n" ); document.write( " |