document.write( "Question 353420: I don't even know where to begin on this problem. This is a question from my college Algebra 2 course.\r
\n" ); document.write( "\n" ); document.write( "A precious metals company receives an order for a block of 160 lbs. of alloy which is 35% silver. The block is made from two individual blocks. The first individual block was 50% silver. The second individual block was 25% silver. What were the weights of the two original blocks?
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Algebra.Com's Answer #252530 by Earlsdon(6294)\"\" \"About 
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Think about the amount of silver in each of the blocks of alloy.
\n" ); document.write( "The 160-lb block has 35% of 160 lbs of silver, or (0.35)(160) lbs of silver.
\n" ); document.write( "The two blocks from which this is made have x(0.5) lbs of silver and (160-x)(0.25) lbs of silver. x is the weight of the block with 50% silver.
\n" ); document.write( "So we set these quantities equal.
\n" ); document.write( "(0.35)(160) = x(0.50)+(160-x)(0.25) Simplify and solve for x.
\n" ); document.write( "56 = 0.5x+40-0.25x Subtract 40 from both sides.
\n" ); document.write( "16 = 0.5x-0.25x Simplify.
\n" ); document.write( "16 = 0.25x Divide both sides by 0.25
\n" ); document.write( "64 = x and...
\n" ); document.write( "160-x = 96
\n" ); document.write( "The weights of the original blocks were:
\n" ); document.write( "64 lbs of the 50% silver alloy and 96 lbs of the 25% silver alloy.
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