document.write( "Question 353429: The sumof the squares of three consecutive positive integers is 77. Find the integers.
\n" ); document.write( "The book gives a hint: if one integer is x, the next consecutive positive integer is x+1, and the third is x+2 \n" ); document.write( "

Algebra.Com's Answer #252519 by robertb(5830) $\"\"$ $\"About$

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$\"x%5E2%2B%28x%2B1%29%5E2%2B%28x%2B2%29%5E2=77\"$ ,
\n" ); document.write( " $\"x%5E2%2Bx%5E2%2B2%2Ax%2B1%2Bx%5E2%2B4%2Ax%2B4=77\"$ ,
\n" ); document.write( " $\"3%2Ax%5E2%2B6%2Ax%2B5+=+77\"$ ,
\n" ); document.write( " $\"3%2Ax%5E2%2B6%2Ax-72+=+0\"$ ,
\n" ); document.write( " $\"x%5E2%2B2%2Ax-24+=0\"$ , after dividing both sides by 3.
\n" ); document.write( " $\"%28x%2B6%29%2A%28x-4%29=0\"$ ,
\n" ); document.write( "This implies that $\"x=-6\"$ or $\"x=4\"$ . We reject the -6 as a solution.
\n" ); document.write( "Therefore the three consecutive positive integers are 4, 5, 6. \n" ); document.write( "

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