document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=353407>Question 353407</A>: <I><SPAN STYLE=\"word-break: break-all;\"> . The measure of the length of a field is 2x + 3 ft and the measure of the width of a field is x + 10 ft. Write an expression for its perimeter </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #252506 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=252506\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length = 2x+3<BR>\n" );
document.write( "width = x+10<BR>\n" );
document.write( "...<BR>\n" );
document.write( "Perimeter = 2(2x+3+x+10)<BR>\n" );
document.write( "P= 2(3x+13)<BR>\n" );
document.write( "P=6x+26<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );