document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=353352>Question 353352</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A garden measuring 12 meters by 16 meters is to have a pedestrian pathway installed all around it, increasing the total area to 285 square meters.  What will be the width of the pathway? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #252486 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=252486\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (16+2x)(12+2x)=285<BR>\n" );
document.write( "192+24x+32x+4x^2=285<BR>\n" );
document.write( "4x^2+56x+192-285=0<BR>\n" );
document.write( "4x^2+56x-93=0<BR>\n" );
document.write( "(2x-3)(2x+31)=0<BR>\n" );
document.write( "2x=3<BR>\n" );
document.write( "x=3/1<BR>\n" );
document.write( "x=1.5 ans. for the width of the pathway.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "(16+2*1.5)(12+2*1.5)=285<BR>\n" );
document.write( "(16+3)(12+3)=285<BR>\n" );
document.write( "19*15=285<BR>\n" );
document.write( "285=285<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );