document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39810>Question 39810</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectange is 6 inches less than twice its width. Find the dimension of the rectangle if its ares is 108 square inches.<BR>\n" );
document.write( "  Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25248 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25248\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width be w.  The length is then 2w - 6.  Multiply them to get the area.<BR>\n" );
document.write( "A = LW<BR>\n" );
document.write( "A = (2w - 6)w<BR>\n" );
document.write( "108 = w(2w - 6)<BR>\n" );
document.write( "2w^2 - 6w - 108 = 0<BR>\n" );
document.write( "w^2 - 3w - 54 = 0<BR>\n" );
document.write( "(w - 9)(w + 6) = 0<BR>\n" );
document.write( "w = 9 or w = -6 (impossible) so<BR>\n" );
document.write( "w = 9 and <BR>\n" );
document.write( "length = 2(9) - 6 = 12 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );