document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39808>Question 39808</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 8 inches greater than its width. Find the width of the rectangle if its area is 105 square inches.<BR>\n" );
document.write( "  Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25246 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25246\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width be w.  The length is then w+8.  We multiply them to get area.<BR>\n" );
document.write( "A = LW<BR>\n" );
document.write( "A = (w+8)w<BR>\n" );
document.write( "105 = w(w+8)<BR>\n" );
document.write( "w^2 + 8w - 105 = 0<BR>\n" );
document.write( "(w + 15)(w - 7) = 0<BR>\n" );
document.write( "w = -15 (impossible) or<BR>\n" );
document.write( "w = 7 inches </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );