document.write( "Question 353272: how many liters of a 14% alcohol solution must be mixed with 20 L of a 50% solution to get a 30% solution? \n" ); document.write( "
Algebra.Com's Answer #252442 by ewatrrr(24785)\"\" \"About 
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Hi,
\n" ); document.write( "Let x represent the \"total\" amount of the 14% solution to be added.
\n" ); document.write( "Then (20L + x) would be the total amount of the final 30% solution.
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\n" ); document.write( "question states
\n" ); document.write( ".14x + .50*20L = .30( 20L + x)
\n" ); document.write( "10L - 6L = .30x - .14x
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\n" ); document.write( "4L = .16x
\n" ); document.write( "x = 25L of the 14% solution needs to be added
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\n" ); document.write( "Check our answer
\n" ); document.write( ".14*25 + .50*20 = .30*45
\n" ); document.write( " 3.5 + 10 = 13.5
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