document.write( "Question 353272: how many liters of a 14% alcohol solution must be mixed with 20 L of a 50% solution to get a 30% solution? \n" ); document.write( "
Algebra.Com's Answer #252442 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! Hi, \n" ); document.write( "Let x represent the \"total\" amount of the 14% solution to be added. \n" ); document.write( "Then (20L + x) would be the total amount of the final 30% solution. \n" ); document.write( ". \n" ); document.write( "question states \n" ); document.write( ".14x + .50*20L = .30( 20L + x) \n" ); document.write( "10L - 6L = .30x - .14x \n" ); document.write( ". \n" ); document.write( "4L = .16x \n" ); document.write( "x = 25L of the 14% solution needs to be added \n" ); document.write( ". \n" ); document.write( "Check our answer \n" ); document.write( ".14*25 + .50*20 = .30*45 \n" ); document.write( " 3.5 + 10 = 13.5 \n" ); document.write( " |