document.write( "Question 353272: how many liters of a 14% alcohol solution must be mixed with 20 L of a 50% solution to get a 30% solution? \n" ); document.write( "
Algebra.Com's Answer #252431 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How many liters of a 14% alcohol solution must be mixed with 20 L of a 50% solution to get a 30% solution? \n" ); document.write( "------------------ \n" ); document.write( "Equation: \n" ); document.write( "alcohol + alcohol = alcohol \n" ); document.write( "0.50*20 + 0.14x = 0.30(20+x) \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "50*20 + 14x = 30*20 + 30x \n" ); document.write( "16x = 20*20 \n" ); document.write( "x = 25 L (amt. of 14% solution needed for the mixture) \n" ); document.write( "============================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |