document.write( "Question 353272: how many liters of a 14% alcohol solution must be mixed with 20 L of a 50% solution to get a 30% solution? \n" ); document.write( "
Algebra.Com's Answer #252431 by stanbon(75887)\"\" \"About 
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How many liters of a 14% alcohol solution must be mixed with 20 L of a 50% solution to get a 30% solution?
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\n" ); document.write( "Equation:
\n" ); document.write( "alcohol + alcohol = alcohol
\n" ); document.write( "0.50*20 + 0.14x = 0.30(20+x)
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "50*20 + 14x = 30*20 + 30x
\n" ); document.write( "16x = 20*20
\n" ); document.write( "x = 25 L (amt. of 14% solution needed for the mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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