document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=353251>Question 353251</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the formulas below for the indicated variable. Show your work. <BR>\n" );
document.write( "E/R+r =1, for R <BR>\n" );
document.write( "I really don't even understand what they mean here, I'd really appreciate some help! Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #252414 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=252414\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "Basically all it's calling for is to get R by itself on one side of the =. <BR>\n" );
document.write( "E/R+r =1, for R <BR>\n" );
document.write( "First we multiply by R to get it out of the denominator. <BR>\n" );
document.write( "E+rR =1R<BR>\n" );
document.write( "Subtract E and R from both sides to get: (Note 1R is the same as R) <BR>\n" );
document.write( "rR-R=-E<BR>\n" );
document.write( "rewrite as:<BR>\n" );
document.write( "R(r-1)=-E<BR>\n" );
document.write( "Now Divide by r-1 to get:<BR>\n" );
document.write( "R=-E/(r-1)<BR>\n" );
document.write( "Make sense?<BR>\n" );
document.write( "RJ<BR>\n" );
document.write( "www.math-unlock.com<BR>\n" );
document.write( " </SPAN>\n" );
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