document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39805>Question 39805</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534432956/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Factor: (15x)y + 25x + 27y + 45\r<BR>\n" );
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document.write( "I am having alot of trouble with factoring so please explain step by step how this is done. The examples in the textbook are hard to follow because I don't know how each step has been arrived at. THANKS! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25240 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25240\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We factor this by a technique known as grouping...we will group them in pairs and factor them separately...so from<BR>\n" );
document.write( "15xy + 25x + 27y + 45 we get<BR>\n" );
document.write( "(15xy + 25x) + (27y + 45) =<BR>\n" );
document.write( "5x(3y + 5) + 9(3y + 5)<BR>\n" );
document.write( "did you get that?<BR>\n" );
document.write( "Now notice there is a common factor in each, that is the 3y + 5, so I can pull it out and we're done...<BR>\n" );
document.write( "(3y + 5)(5x + 9) </SPAN>\n" );
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