document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39804>Question 39804</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1/y-1+5/12=-2/3y-3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25239 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25239\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We multiply all by the lowest common denominator to clear fractions...in this case 12(y - 1)...so we get<BR>\n" );
document.write( "1/y-1 + 5/12 = -2/3y-3<BR>\n" );
document.write( "12(y - 1)[1/y-1 + 5/12 = -2/3y-3]<BR>\n" );
document.write( "12 + 5(y-1) = -8<BR>\n" );
document.write( "12 + 5y - 5 = -8<BR>\n" );
document.write( "5y = -15<BR>\n" );
document.write( "y = -3 </SPAN>\n" );
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