document.write( "Question 353193: How do I use the quadratic formula to solve this x^2-3x=-6 ? \n" ); document.write( "
Algebra.Com's Answer #252378 by ewatrrr(24785)\"\" \"About 
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Hi,\r
\n" ); document.write( "\n" ); document.write( "x^2-3x=-6
\n" ); document.write( "Put into the following form:
\n" ); document.write( "x^2 - 3x + 6 = 0
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\n" ); document.write( "Using the quadratic formula: In this case a = 1, b = -3 and c = 6
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
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\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+%28-3%29%5E2-4%2A6+%29%29%2F2+\"
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\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28-15%29%29%2F2+\"
\n" ); document.write( "Note: there are no solutions among real numbers
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\n" ); document.write( "In the field of imaginary numbers: solution would be as follows
\n" ); document.write( "\"x+=+%283+%2B-+i%2Asqrt%2815%29%29%2F2+\"
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