document.write( "Question 353174: factor completely:
\n" ); document.write( "2x^2-20x+50-18y^2=0 \n" ); document.write( "
Algebra.Com's Answer #252374 by CharlesG2(834)\"\" \"About 
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factor completely:
\n" ); document.write( "2x^2-20x+50-18y^2=0\r
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\n" ); document.write( "\n" ); document.write( "this is not a quadratic equation,
\n" ); document.write( "quadratic equations are of form ax^2 + bx + c = 0
\n" ); document.write( "however let's see if it can be factored\r
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\n" ); document.write( "\n" ); document.write( "2x^2 - 20x + 50 - 18y^2 = 0
\n" ); document.write( "2x^2 - 20x + 50 = 18y^2 (brought the y^2 term to other side)
\n" ); document.write( "x^2 - 10x + 25 = 9y^2 (divided both sides by 2)
\n" ); document.write( "(x - 5)(x - 5) = 3y * 3y (found square roots both sides)
\n" ); document.write( "(the (x-5)(x-5) does multiply with FOIL out to x^2-10x+25)
\n" ); document.write( "x - 5 = 3y
\n" ); document.write( "solving for x --> x = 3y + 5
\n" ); document.write( "solving for y --> -3y = -x + 5 --> 3y = x - 5 --> y = (1/3)x - 5/3\r
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\n" ); document.write( "\n" ); document.write( "factored:
\n" ); document.write( "2x^2 - 20x + 50 - 18y^2 = 0
\n" ); document.write( "2(x^2 - 10x + 25 - 9y^2) = 0
\n" ); document.write( "2((x - 5)^2 - (3y)^2) = 0\r
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