document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=352352>Question 352352</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -2(3a-b)=c;b<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #252361 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=252361\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given -2(3a-b)= c, solve for b.  This is what the question is asking you to do.\r<BR>\n" );
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document.write( "-2(3a - b) = c\r<BR>\n" );
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document.write( "-6a + 2b = c\r<BR>\n" );
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document.write( "2b = 6a + c\r<BR>\n" );
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document.write( "b = (6a + c)/2\r<BR>\n" );
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document.write( "Done!<BR>\n" );
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