document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=353100>Question 353100</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The number 2^48 - 1 divisible by two numbers between 60 and 70. Their sum is:\r<BR>\n" );
document.write( "\n" );
document.write( "(a) 124 (b) 128  (c) 132 (d) 136  (e) None of the above<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #252350 by </B><A HREF=/tutors/aboutme.mpl?userid=CharlesG2><B>CharlesG2(834)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharlesG2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=252350\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The number 2^48 - 1 divisible by two numbers between 60 and 70. Their sum is:\r<BR>\n" );
document.write( "\n" );
document.write( "(a) 124 (b) 128  (c) 132 (d) 136  (e) None of the above\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "http://www.wolframalpha.com/input/?i=factor+%282%5E48%29-1<BR>\n" );
document.write( "(used factor 2^48 - 1 to get factors)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "prime factorization: 3^2 * 5 * 7 * 13 * 17 * 97 * 241 * 257 * 673<BR>\n" );
document.write( "this gives 768 divisors according to wolframalpha<BR>\n" );
document.write( "here is the ones up to 105:<BR>\n" );
document.write( "1,3,5,7,9,13,15,17,21,35,39,45,51,63,65,85,91,97,105\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "the 2 numbers between 60 and 70 are 63 and 65<BR>\n" );
document.write( "63 + 65 = 128, answer is (b) 128<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );