document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=352986>Question 352986</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x-32/2=24+5x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #252257 by </B><A HREF=/tutors/aboutme.mpl?userid=kking001><B>kking001(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kking001><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=252257\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = -13.3333-- <BR>\n" );
document.write( "Find this by making 32/2 16 because 32/2 is 16. so it would show 2x-16=24+5x then you would add 16 to both sides of the like terms so it would show 2x=40+5x then after that you would subtract 5x from 2x because they are like terms and it would show -3x=40 you must then divide both sides by 3 to isolate the variable so that it shows -x = 13.3333-- then you multiply -x by -1 so that you can isolate the variable in a positive number (remember both sides you must do.)so it would show x = -13.3333-- </SPAN>\n" );
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