document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=352283>Question 352283</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me please?<BR>\n" );
document.write( "Thank you very much! <BR>\n" );
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document.write( "This is the exercise:\r<BR>\n" );
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document.write( "Without solving for the number of terms, determine the sum of the series, below, using a formula. Do not round answer, please. <BR>\n" );
document.write( "144+72+36+...+0.5625 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #252183 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=252183\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the ratio between consecutive terms (r) is 1/2\r<BR>\n" );
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document.write( "the sum of the series is ___ [(first term)-(last term)] / (1 - r) </SPAN>\n" );
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