document.write( "Question 352819: I don't understand how to arrive at the answers to the following problems:\r
\n" ); document.write( "\n" ); document.write( "A)One number is 2 more than 5 times another. Their product is 24. Find the numbers.\r
\n" ); document.write( "\n" ); document.write( "B) One number is 4 times another. Their product is 4 times their sum. Find the numbers.\r
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Algebra.Com's Answer #252182 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll do the first one to get you started\r
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\n" ); document.write( "\n" ); document.write( "\"One number is 2 more than 5 times another\" means that \"y=5x%2B2\" and \"Their product is 24\" tells us that \"xy=24\" (x times y = 24)\r
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\n" ); document.write( "\n" ); document.write( "\"xy=24\" Start with the second equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%285x%2B2%29=24\" Plug in \"y=5x%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "\"5x%5E2%2B2x=24\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"5x%5E2%2B2x-24=0\" Subtract 24 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"ax%5E2%2Bbx%2Bc\" where \"a=5\", \"b=2\", and \"c=-24\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%282%29+%2B-+sqrt%28+%282%29%5E2-4%285%29%28-24%29+%29%29%2F%282%285%29%29\" Plug in \"a=5\", \"b=2\", and \"c=-24\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+4-4%285%29%28-24%29+%29%29%2F%282%285%29%29\" Square \"2\" to get \"4\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+4--480+%29%29%2F%282%285%29%29\" Multiply \"4%285%29%28-24%29\" to get \"-480\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+4%2B480+%29%29%2F%282%285%29%29\" Rewrite \"sqrt%284--480%29\" as \"sqrt%284%2B480%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+484+%29%29%2F%282%285%29%29\" Add \"4\" to \"480\" to get \"484\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+484+%29%29%2F%2810%29\" Multiply \"2\" and \"5\" to get \"10\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+22%29%2F%2810%29\" Take the square root of \"484\" to get \"22\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B+22%29%2F%2810%29\" or \"x+=+%28-2+-+22%29%2F%2810%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2820%29%2F%2810%29\" or \"x+=++%28-24%29%2F%2810%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+2\" or \"x+=+-12%2F5\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the possible answers are \"x+=+2\" or \"x+=+-12%2F5\" \r
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\n" ); document.write( "If you want integer only answers, then the only solution is \"x=2\"\r
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\n" ); document.write( "\n" ); document.write( "So one number is 2 and the other is \"y=5%282%29%2B2=10%2B2=12\"\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers are 2 and 12.
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