document.write( "Question 352791: Are the inequalities x > -8 and –x < 8 equivalent? \n" ); document.write( "

Algebra.Com's Answer #252166 by jim_thompson5910(35256) $\"\"$ $\"About$

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Yes they are. If you take the first inequality $\"x%3E-8\"$ and you subtract 'x' from both sides, you get $\"0%3E-8-x\"$ . Now add 8 to both sides to get $\"8%3E-x\"$ . Finally, flip the inequality to get $\"-x%3C8\"$ . So this shows that $\"x+%3E+-8\"$ and $\"-x+%3C+8\"$ are equivalent. \n" ); document.write( "

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