document.write( "Question 352719: find three consecutive odd integers such that the sum of the first, twice the second, and three times the third is 94 \n" ); document.write( "

Algebra.Com's Answer #252122 by Alan3354(69443) $\"\"$ $\"About$

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find three consecutive odd integers such that the sum of the first, twice the second, and three times the third is 94
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\n" ); document.write( "The easy way:
\n" ); document.write( "The sum is aprox 6 times the 1st integer
\n" ); document.write( "94/6 = 15.xxx
\n" ); document.write( "--> 13, 15 & 17
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\n" ); document.write( "The hard way:
\n" ); document.write( "n, n+2 and n+4 are the integers
\n" ); document.write( "n + 2(n+2) + 3(n+4) = 94
\n" ); document.write( "6n + 16 = 94
\n" ); document.write( "6n = 78
\n" ); document.write( "n = 13
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