document.write( "Question 39779: How many litres of 14% alcohol solution must be mixed with 20L of a 50% solution to get a 30% solution. \r
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document.write( "How do you set this problem up. I thought .14x+.5(x+20)=.3 but I am way off. \n" );
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Algebra.Com's Answer #25206 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How many litres of 14% alcohol solution must be mixed with 20L of a 50% solution to get a 30% solution. \r \n" ); document.write( "\n" ); document.write( "Let \"x\" be amount of 14% solution. \n" ); document.write( "Then 0.14x liters of this is alcohol. \n" ); document.write( "Also, 0.50(20L)= 10 liters is alcohol. \n" ); document.write( "EQUATION: \n" ); document.write( "alcohol + alcohol = 0.30(x+20)liters \n" ); document.write( "0.14x + 10 = 0.30x + 6 \n" ); document.write( "Multiply through by 100 to get: \n" ); document.write( "14x + 1000 = 30x + 600 \n" ); document.write( "-16x = -400 \n" ); document.write( "x= 25 liters (this is the amount of 14% solution you need to add) \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |