document.write( "Question 352664: Solve for the variable in each equation below. Show all your work. Provide a check for each answer. If a solution is undefined, state that in your answer.\r
\n" ); document.write( "\n" ); document.write( "x-2/x+1 = x+1/x-2\r
\n" ); document.write( "\n" ); document.write( "CHECK.\r
\n" ); document.write( "\n" ); document.write( "It seems to me that the x-2's would cancel eachother out, and the same for x+1, am I correct? Please help me! Thanks so much!
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Algebra.Com's Answer #252059 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Solve for the variable in each equation below. Show all your work. Provide a check for each answer. If a solution is undefined, state that in your answer.
\n" ); document.write( "x-2/x+1 = x+1/x-2
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\n" ); document.write( "You must not cancel terms, only factors.
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\n" ); document.write( "Cross multiply to get:
\n" ); document.write( "(x-2)^2 = (x+1)^2
\n" ); document.write( "x^2-4x+4 = x^2+2x+1
\n" ); document.write( "6x = 3
\n" ); document.write( "x = 1/2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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