document.write( "Question 351957: torque left home on his bicycle at 9:00 am traveling at an average rate of 12 mph. at noon, torque's brother set out after him on a motorcycle, following the same route, averaging the 39 mph. How far had torque traveled when his brother caught up? \n" ); document.write( "
Algebra.Com's Answer #252023 by Alan3354(69443)\"\" \"About 
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torque left home on his bicycle at 9:00 am traveling at an average rate of 12 mph. at noon, torque's brother set out after him on a motorcycle, following the same route, averaging the 39 mph. How far had torque traveled when his brother caught up?
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\n" ); document.write( "In 3 hours, torque had gone 36 miles (12 mph * 3 hr)
\n" ); document.write( "His brother's relative speed is 27 mph (39 - 12 mph)
\n" ); document.write( "He overtakes him in 36/27 hours = 4/3 hours
\n" ); document.write( "In 4/3 hours, the brother will go (4/3)*39 miles
\n" ); document.write( "= 52 miles, obviously the same distance as torque.
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